Find the the digits of number x that satisfy the mutiply of all digits of x equal to x^2-10x-22?

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Answer 1 · 2018-08-08T22:42:28

$x = 49 + 5 i, 49 - 5 i$ $x=49+5i, 49-5i$
2 solutions

I'm pretty sure you are asking for the possible solutions

$x^{2} - 10 x - 22$ $x^2-10x-22$

$x = \frac{10 + \sqrt{- 10^{2}} - (4 \cdot 1 \cdot - 22)}{2 \cdot 1}$ $x=(10+sqrt(-10^2)-(4*1*-22))/(2*1)$

$x = \frac{10 + 10 i + 88}{2}$ $x=(10+10i+88)/2$

$x = 49 + 5 i$ $x=49+5i$

$x = \frac{10 - \sqrt{- 10^{2}} - (4 \cdot 1 \cdot - 22)}{2 \cdot 1}$ $x=(10-sqrt(-10^2)-(4*1*-22))/(2*1)$

$x = \frac{10 - 10 i + 88}{2}$ $x=(10-10i+88)/2$

$x = 49 - 5 i$ $x=49-5i$