Question

What is the antiderivative of `m(x) = (-2/y^3)`?

Answer 1

`M(x)=-2/y^3x+C`, `C in RR`

Explanation:

you have `m(x)=-2/y^3`, because m depends of x, you consider `-2/y^3` as a constant.

So:

`M(x)=intm(x)dx=int-2/y^3dx=-2/y^3x+C`, `C in RR`

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