When air at 300k and 1 atm pressure is compressed to one.twentieth of its original volume and 30 atm pressure the new temperature will be?

1 Answer
A08
Aug 9, 2018

Using the Gas equation for gases and inserting given values we get

(P_1V_1)/T_1=(P_2V_2)/T_2
(1xxV_1)/300=(30xxV_1/20)/T_2
=>T_2=(30xxV_1/20)/((1xxV_1)/300)
=>T_2=30xx300/20
=>T_2=450\ sfK

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