Question

When air at 300k and 1 atm pressure is compressed to one.twentieth of its original volume and 30 atm pressure the new temperature will be?

Answer 1

Using the Gas equation for gases and inserting given values we get

`(P_1V_1)/T_1=(P_2V_2)/T_2`
`(1xxV_1)/300=(30xxV_1/20)/T_2`
`=>T_2=(30xxV_1/20)/((1xxV_1)/300)`
`=>T_2=30xx300/20`
`=>T_2=450\ sfK`