How do you graph the line #3x-4y-8=0#?

3 Answers
Aug 9, 2018

you will have to graph the line

#y=3/4x-2#

where #3/4# is the gradient of the line and it has a #y#-intercept of #-2#.

Explanation:

you would have to rearrange the given equation into the

#y=mx+c#

form, where #m# is the gradient of the straight line and #c# is the #y#-intercept.

graph{3/4x-2 [-10, 10, -5, 5]}

Aug 10, 2018

As below.

Explanation:

#3x - 4y - 8 = 0#

For x = 0, -4y - 8 = 0 " or " y-intercept = -2#

For y = 0, 3x = 8 " or " x-intercept = 8/3#

Now we know, x intercept as 8/3 and y intercepts as -2#

We can mark the intercepts on the graph and join them to draw the line.

graph{(3/4)x - 2 [-10, 10, -5, 5]}

Aug 10, 2018

Graph the line by finding the intercepts.

Explanation:

Graph:

#3x-4y-8=0#

Add #8# to both sides of the equation to get the equation into standard form:

#Ax+By=C#, so that

#3x-4y=8#

You can graph this equation by finding the intercepts.

X-intercept: value of #x# when #y=0#

Substitute #0# for #y# and solve for #x#.

#3x-4(0)=8#

#3x=8#

Divide both sides by #3#.

#(3x)/3=8/3#

#x=8/3# or #~~2.667#

The x-intercept is #(8/3,0)# or #~~2.667# Plot this point.

Y-intercept: value of #y# when #x=0#.

Substitute #0# for #x# and solve for #y#.

#3(0)-4y=8#

#-4y=8#

Divide both sides by #-4#.

#(-4y)/(-4)=8/(-4)#

#y=-8/4#

Simplify.

#y=-2#

The y-intercept is #(0,-2)# Plot this point.

Draw a straight line through the points.

graph{3x-4y=8 [-10, 10, -5, 5]}