How do you evaluate log_2 8?
2 Answers
Aug 10, 2018
Explanation:
"using the "color(blue)"law of logarithms"
•color(white)(x)log_b x=nhArrx=b^n
"let "log_2 8=nhArr8=2^nrArrn=3
rArrlog_2 8=3
Aug 11, 2018
Using logarithm properties we have