How do you evaluate log_2 8?

2 Answers
Aug 10, 2018

3

Explanation:

"using the "color(blue)"law of logarithms"

•color(white)(x)log_b x=nhArrx=b^n

"let "log_2 8=nhArr8=2^nrArrn=3

rArrlog_2 8=3

Using logarithm properties we have

log_2 8=log_2 2^3=3*log_2 2=3