Question

How do you find the center and radius of the circle `2(x-3)²+2y²=8`?

Answer 1

Divide by `2` both sides of the equation to get

`(x-3)^2+y^2=4`

or

`(x-3)^2+(y-0)^2=2^2`

Hence the center is the point `(3,0)` and the radius is `r=2`