How do you expand #log (6/5)^6#? Precalculus Properties of Logarithmic Functions Common Logs 1 Answer Shwetank Mauria Aug 12, 2018 #log(6/5)^6=6log6-6log5# Explanation: As #log(a/b)=loga-logb# and #loga^m=mloga# hence #log(6/5)^6# = #6log(6/5)# = #6(log6-log5)# = #6log6-6log5# Answer link Related questions What is the common logarithm of 10? How do I find the common logarithm of a number? What is a common logarithm or common log? What are common mistakes students make with common log? How do I find the common logarithm of 589,000? How do I find the number whose common logarithm is 2.6025? What is the common logarithm of 54.29? What is the value of the common logarithm log 10,000? What is #log_10 10#? How do I work in #log_10# in Excel? See all questions in Common Logs Impact of this question 3179 views around the world You can reuse this answer Creative Commons License