How do you graph # y=cot(2x-pi/2)#?

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Answer 1 · 2018-08-13T01:28:28

See explanation and graph

#y = cot ( 2 x - pi/2 ) = - cot ( pi/2 - 2 x ) = - tan 2 x,#

#x ne# ( the asymptotic zero of the denominator sin 2x ) #k/2pi#.

k = 0, +-1, +-2, +_3, ...#

The period# = pi/2#.

The axis is y = 0.

The infinite-arm wave amplitude #= 1/2 ( pi/2 ) = pi/4#. See graph.
graph{(y+tan (2x))(y+0x)=0[-pi/2 pi/2 -pi/4 pi/4 ] }