How to express this series in summation notation? 27+18+12+8

1 Answer
Narad T.
Aug 13, 2018

The answer is =sum_(k=0)^3 2^k*3^(3-k)

Explanation:

The sum is

S=(2^0xx3^3)+(2^1xx3^2)+(2^2xx3^1)+(2^3xx3^0)

=sum_(k=0)^3 2^k*3^(3-k)

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