How are temperature on Celsius and Kelvin scales related?

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Answer 1 · 2018-08-13T16:32:55

Well, on the Celsius scale....we set $0$ $""^@C$ $-=$ $"the normal freezing point of water"$

And on the $"temperatura assoluta"$ scale, $"the normal freezing point of water"-=273.15*K$ ...

Here, the $"absolute or Kelvin temperature scale"$ sets ZERO at $-273.15$ $""^@C$ ...the point at which all molecular motion ceases...

Answer 2 · 2018-08-13T16:57:20

$"Temp"("K") = "Temp"(""^@"C") + 273.15$

$"Temp"(""^@"C") = "Temp"("K") - 273.15$

$0^@"C"= "273.15 K"$

$"0 K" = -273.15^@"C"$

A change in temperature of $1$ Kelvin is equivalent to a change of $1^@"C"$ , so they have the same magnitude.

However, the Kelvin scale is based on $"0 K" \ =$ $"absolute zero"$ (the coldest possible temperature where atoms have no thermal movement).

The Celsius scale is based on $0^@"C" = "freezing point of pure water"$ (at standard sea-level pressure).

The two scales are related by a difference of $273.15$ .

$T("K") = T(""^@"C") + 273.15$

$T(""^@"C") = T("K") - 273.15$