Question

0.345 moles of `CH_4` is placed in a 15.0 L container at a temperature of 25.2°C. What is the pressure in atm exerted by the gas?

Answer 1

Approx. `1/2*"atm"`

Explanation:

`P=(nRT)/V` `=` `(0.345*molxx0.00821*L*atm*K^-1*mol^-1xx298.2*K)/(15.0*L)`

`=` `??*atm`