Now we perform hydrohalogenation with DBr-=""^(2)HBrDBr≡2HBr so that we can follow the process. We start with propylene...the which reacts with the protium ion....
H_2C=CH-CH_3 + DBr rarr underbrace(H_2DC-stackrel(+)CH-CH_3)_"stabilized intermediate"+Br^(-)
" "underbrace(H_2stackrel(+)C-CHD-CH_3)_"primary carbocation"
From the unsymmetrical olefin, the protium ion of ""^2HBr can add to "carbon 1" to give a 2^@ "carbocation", or add to "carbon 2" to give a 1^@ "carbocation". We assume the 2^@ "carbocation" is stabilized with respect to the 1^@ "carbocation"..and so the reaction should follow the lower energy route.
And so the end result should be the secondary alkyl halide as the major product....
H_2C=CH-CH_3 + DBr rarr underbrace(H_2DC-CHBr-CH_3)_"major product"
" "underbrace(BrH_2C-CHD-CH_3)_"minor product"
Do you follow? If no, we will try again...