$1$ $1$ mole of $N_{2}$ $"N"_2$ reacts with $Ca$ $"Ca"$ to form ${Ca}_{3} N_{2}$ $"Ca"_3"N"_2$ . How many moles of ${Ca}_{3} N_{2}$ $"Ca"_3"N"_2$ are produced?

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$1$ $1$ mole of $N_{2}$ $"N"_2$ reacts with $Ca$ $"Ca"$ to form ${Ca}_{3} N_{2}$ $"Ca"_3"N"_2$ . How many moles of ${Ca}_{3} N_{2}$ $"Ca"_3"N"_2$ are produced?

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Answer 1 · 2017-12-20T12:08:40

$1 mole$ $"1 mole"$

Explanation:

The idea here is that you need to write and examine the balanced chemical equation that describes the formation of calcium nitride from the reaction of calcium metal and nitrogen gas.

$3 {Ca}_{(s)} + N_{2 (g)} \to {Ca}_{3} N_{2 (s)}$ $3"Ca"_ ((s)) + "N"_ (2(g)) -> "Ca"_ 3"N"_ (2(s))$

Notice that it takes $3$ $3$ moles of calcium to react with $1$ $1$ mole of nitrogen gas and produce $1$ $1$ mole of calcium nitride.

In your case, you know that exactly $1$ $1$ mole of nitrogen gas is taking part in this reaction, so you can that the reaction also consumed $3$ $3$ moles of calcium metal.

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$1$ $1$ mole of $N_{2}$ $"N"_2$ reacts with $Ca$ $"Ca"$ to form ${Ca}_{3} N_{2}$ $"Ca"_3"N"_2$ . How many moles of ${Ca}_{3} N_{2}$ $"Ca"_3"N"_2$ are produced?

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11 mole of N2"N"_2 reacts with Ca"Ca" to form Ca3N2"Ca"_3"N"_2. How many moles of Ca3N2"Ca"_3"N"_2 are produced?

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$1$ $1$ mole of $N_{2}$ $"N"_2$ reacts with $Ca$ $"Ca"$ to form ${Ca}_{3} N_{2}$ $"Ca"_3"N"_2$ . How many moles of ${Ca}_{3} N_{2}$ $"Ca"_3"N"_2$ are produced?