$10 c m^{3}$ $10cm^3$ of normal specimen of human blood contains 1.2g of hemoglobin. How many grams does $35 c m^{3}$ $35cm^3$ of the same blood contain?

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Answer 1 · 2016-09-17T16:00:05

$4.2 g$ $4.2g$

You can do this using 2 methods:

Method 1: The unitary method where you work out for 1 $c m^{3}$ $cm^3$

In $10 c m^{3}$ $10cm^3$ of blood .... $1.2 g$ $1.2g$

In $1 c m^{3}$ $1cm^3$ of blood .... $1.2 \div 10 = 0.12 g$ $1.2 div 10 = 0.12g$

In $35 c m^{3}$ $35cm^3$ of blood .... $35 \times 0.12 g = 4.2 g$ $35xx0.12g = 4.2g$

Method 2: The direct proportion or comparison method

$\frac{10 c m^{3}}{35 c m^{3}} = \frac{1.2 g}{x g} \to$ $(10cm^3)/(35cm^3) = (1.2g)/(x g)" "rarr$ cross-multiply

$10 \times x = 35 \times 1.2$ $10xx x = 35 xx1.2$

$x = \frac{35 \times 1.2}{10}$ $x = (35xx1.2)/10$

$x = 4.2 g$ $x = 4.2g$

10cm310cm^3 of normal specimen of human blood contains 1.2g of hemoglobin. How many grams does 35cm335cm^3 of the same blood contain?