2 ships X&Y are traveling in different directions at equal speed. the actual direction of motion of X is due North but to an observer on Y the apparent direction of motion of X is north east. the actual direction of motion of Y as observed from shore is?

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options..
a) east b) West c) south east d) south west

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Answer 1 · 2018-02-03T14:45:32

Let, Velocity of ship $X$ $X$ is $V x$ $Vx$ ,that of $Y$ $Y$ is $V y$ $Vy$ and velocity of Ship $X$ $X$ w.r.t $Y$ $Y$ is $V x y$ $Vxy$

So, $V x y = V x - V y = V x + (- V y)$ $Vxy = Vx-Vy=Vx+(-Vy)$

Now,given, $V x = V y$ $Vx= Vy$

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And, angle between $V x y$ $Vxy$ and $V x$ $Vx$ is $45$ $45$ degrees

So, if the angle between, $V x$ $Vx$ and $- V y$ $-Vy$ is $θ$ $theta$

$θ = 90$ $theta = 90$ degrees ( as two vectors of same magnitude when act at 90 degrees,their resultant makes 45 degrees with each of them)

So, $- V y$ $-Vy$ is directed along east,hence $V y$ $Vy$ is directed along West