$2NaN_3(s) -> 2Na(s) + 3N_2(g)$ Given the equation, how many moles of $N_2$ are produced by the decomposition of 1.50 mol of $NaN_3$ ?

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Answer 1 · 2016-09-12T17:48:44

2.25mol.

The equation tells you that for every 2 moles of $NaN_3$ decomposed, you get 3 moles of $N_2$ out.

So simply take the 1.5 mol and divide by two, then multiply by 3.

2NaN_3(s) -> 2Na(s) + 3N_2(g)2NaN_3(s) -> 2Na(s) + 3N_2(g) Given the equation, how many moles of N_2N_2 are produced by the decomposition of 1.50 mol of NaN_3NaN_3?