Question

3.01e22 Ag+ ions is present in? options a) 85 grams of AgNO3 b) 0.85g AgNO3 c) 8.5g AgNO3 d) 18.5g AgNO3

Answer 1

`8.5` g of `AgNO_3`

Explanation:

`1` mole `= 6.023 xx 10^23` ions
`Ag^+ =` `3.01 xx 10^22` ions

No. of moles of `Ag^+ =`(`3.01` x `10^22` ions)/(`6.023 xx 10^23` ions) `=`

`0.0499` moles

Molar mass of `AgNO_3` `=` `169.87 g"/"mol`

Mass of `AgNO_3` `=` `0.0499` moles `xx 169.87 g"/"mol = 8.47 g`

`AgNO_3 -> Ag^+ \ + \ NO_3^-`