#5^(2n-1)=2" "rArr " "25^(3n-2=?#
#"let us rearrange the the expression of "5^(2n-1)=2#
#5^2n-1=5^(2n)*5^(-1)=5^(2n)/5#
#5^(2n)/5=2#
#5^(2n)=10#
#"now ,let us rearrange the expression o f "25^(3n-2#
#25^(3n-2)=5^(2(3n-2))=5^(6n-4)=5^(6n)*5^(-4)=5^(6n)/5^4#
#=(5^(2n)*5^(2n)*5^(2n))/5^4=(10*10*10)/5^4=1000/625=8/5#