Question

5.85 g of NaCl is dissolved in 1 L of pure water . How do you calculate the number of ions in 1mL of this solution?

Answer 1

5.85 g of NaCl = 0.1 mol
1 L solution contain NaCl = 0.1 mol
1 ml solution contain NaCl = 0.0001 mol

one NaCl ionized Na+ and Cl- so that produce 2 ions

Total ion mole in 1 ml = 2x0.0001 mol

Number of iron in 1 ml= `2`x`0.0001`x`6.023`x`10^23`

Number of iron in 1 ml = `1.2`x`10^20` ions