Question #dc381

1 Answer
Jan 14, 2014

42.88 % "C"C by mass and 57.12 % "O"O by mass

Explanation:

Percentage composition is the percentage by mass of each element in a compound.

"% by mass" = "mass of element"/"total mass of all elements" × 100%% by mass=mass of elementtotal mass of all elements×100%

To find the % composition of "CO"CO, you calculate the % by mass of each element in a given mass of "CO"CO. It is simplest to use 1 mol of "CO"CO.

1 mol "CO"CO contains 1 mol of "C"C and 1 mol of "O"O.

28.01 g "CO"CO contain 12.01 g "C"C and 16.00 g "O"O.

"% C by mass" = "mass of C"/"mass of CO" × 100 % = (12.01 color(red)(cancel(color(black)("g"))))/(28.01 color(red)(cancel(color(black)("g")))) × 100 % = 42.88 %

"% O by mass" = "mass of O"/"mass of CO" × 100 % = (16.00 color(red)(cancel(color(black)("g"))))/(28.01 color(red)(cancel(color(black)("g")))) × 100 % = 57.12 %