Question #179b0

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Question #179b0

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Answer 1 · 2014-01-23T03:29:37

The standard electron configuration for magnesium would be $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2}$ $1s^2 2s^2 2p^6 3s^2$

The noble gas one row above magnesium is neon. Neon would have an electron configuration of $1 s^{2} 2 s^{2} 2 p^{6}$ $1s^2 2s^2 2p^6$ .

Therefore, $1 s^{2} 2 s^{2} 2 p^{6}$ $1s^2 2s^2 2p^6$ can be replaced by the noble gas [Ne].
This makes the noble gas configuration of magnesium
[Ne] $3 s^{2}$ $3s^2$

I hope this is helpful.
SMARTERTEACHER

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Answer 2 · 2015-03-15T00:19:04

The following video discusses how to find the noble gas electron configuration for magnesium.

video from: Noel Pauller

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Question #179b0

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