Question #3f1d9

1 Answer
Apr 4, 2014

For this solution, since the reaction is not at Standard Temperature and Pressure (STP), you will need to use the Ideal Gas Law to solve for moles of CO2 and then Stoichiometry to solve for the grams of CaCO3.

To begin with we find the knowns and unknowns for the Ideal Gas Law, PV = nRT.

P = 1.00 atm
V = 3.45 L
n = ??
R = 0.0821 atmLmolK
T = 298 K

PV = nRT can be rearranged n=PVRT

n=(1.00atm)(3.45L)(.0821atmLmolK)(298K)

n = 0.14 moles CO2

Now you can use the balanced chemical equation and stoichiometry to solve for the grams of CaCO3

moles moles grams

0.14molCO2x1molCaCO31molCO2x100.0869gCaCO31molCaCO3=14.01gCaCO3

I hope this was helpful.
SMARTERTEACHER