$5400 is invested, part of it at 12% and part of it at 9%. For a certain year, the total yield is 576.00. How much was invested at each rate?

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$5400 is invested, part of it at 12% and part of it at 9%. For a certain year, the total yield is 576.00. How much was invested at each rate?

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Answer 1 · 2016-11-19T04:17:42

$$ 3000$ $$3000$ was invested at $12 %$ $12%$ and $$ 2400$ $$2400$ was invested at $9 %$ $9%$

Explanation:

Let the money invested at $12 %$ $12%$ be $$ x$ $$x$ . Interest on it for a year will be $\frac{12}{100} \times x$ $12/100 xx x$ .

Then money invested at $9 %$ $9%$ would be $$ (5400 - x)$ $$(5400-x)$ and interest on it for a year will be $\frac{9}{100} \times (5400 - x)$ $9/100 xx (5400-x)$ .

As total yield is $576$ $576$ , we have

$\frac{12 x}{100} + \frac{9 (5400 - x)}{100} = 576$ $(12x)/100+(9(5400-x))/100=576$ - multiplying both sides by $100$ $100$

or $12 x + 9 (5400 - x) = 57600$ $12x+9(5400-x)=57600$

or $12 x + 48600 - 9 x = 57600$ $12x+48600-9x=57600$

or $3 x = 57600 - 48600 = 9000$ $3x=57600-48600=9000$

i.e. $x = \frac{9000}{3} = 3000$ $x=9000/3=3000$ and $5400 - x = 2400$ $5400-x=2400$

Hence, $$ 3000$ $$3000$ was invested at $12 %$ $12%$ and $$ 2400$ $$2400$ was invested at $9 %$ $9%$

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$5400 is invested, part of it at 12% and part of it at 9%. For a certain year, the total yield is 576.00. How much was invested at each rate?

1 Answer

Explanation:

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