Boyle's law states that the pressure and the volume of a gas are proportional to one another, if temperature and the number of moles are kept constant.
Starting from the ideal gas law, PV=nRT, and taking into account the premise that moles and temperature are kept constant, we get
V=1P⋅nRT→V=1P⋅k, where
k=nRT=constant
Now, a plot of V vs 1P will look like this (the graph on the right)
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Notice that the line starts from the origin, which is consistent with the premise that b=0→ from y=mx+b
SInce your linear equation is given,
y=2060.1x+2⋅10−5, we can assume that 2⋅10−5 is negligible; all you need now is a second point on the line in order to express the slope. The most obvious point on this graph is (0,0), which will give
m=y1−y2x1−x2=3.1146−00.001526618−0=2040.2, which represents the slope of the graph V vs 1P, and the constant k=nRT.
