Question

Question #3a0fa

Answer 1

Equation of a Circle

The equation of a circle with radius `r`, centered at `(x_0,y_0)` is

`(x-x_0)^2+(y-y_0)^2=r^2`

---

Since the center is `(x_0,y_0)=(-2,-1)` and it is `1` unit away from the `x`-axis, which gives `r=1`, we have

`(x+2)^2+(y+1)^2=1^2`

---

I hope that this was helpful.