Question #17cec

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Question #17cec

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Answer 1 · 2014-12-01T17:23:54

This problem can be solved using Boyle's law, which states that pressure and volume have an inverse relationship, such that if the pressure increases, the volume decreases, and if the pressure decreases, the volume increases. The formula for Boyle's law is:

$P_{1} V_{1}$ $"P"_1"V"_1$ = $P_{2} V_{2}$ $"P"_2"V"_2$

Given:
$P_{1}$ $"P"_1$ = $822 torr$ $"822 torr"$
$V_{1}$ $"V"_1$ = $40.0L$ $"40.0L"$
$V_{2}$ $"V"_2$ = $56.0L$ $"56.0L"$

Unknown:
$P_{2}$ $"P"_2$

Solution:

Divide both sides of the equation by $V_{2}$ $"V"_2"$ to isolate $P_{2}$ $"P"_2$ . Solve for $P_{2}$ $"P"_2$ .

$P_{2}$ $"P"_2$ = $P_{1} V_{1} {/V}_{2}$ $"P"_1"V"_1"/V"_2$ = $(822 torr)(40.0L)/56.0L$ $"(822 torr)(40.0L)/56.0L"$ = $587 torr$ $"587 torr"$

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Question #17cec

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