Question #00893

Question

Question #00893

1 Answer

Impact of this question

2287 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2014-12-03T19:17:01

If I understood the question correctly, the volume will be $V = 69.7 L$ $V = 69.7 L$

Basically, you are dealing with the combustion of benzene, $C_{6} H_{6}$ $C_6H_6$ . Starting from the balanced reaction,

$2 C_{6} H_{6} + 15 O_{2} \to 12 C O_{2} + 6 H_{2} O$ $2C_6H_6 + 15O_2 -> 12CO_2 + 6H_2O$

you can see that the benzene to oxygen ratio is $2 : 15$ $2:15$ ; that is, for every 2 moles of benzene you need 15 moles of oxygen.

Your initial values are $0.5$ $0.5$ moles for $C_{6} H_{6}$ $C_6H_6$ and $3.75$ $3.75$ moles for $O_{2}$ $O_2$ , which correspond to the balanced equation's ratio. This means that neither the benzene, nor the oxygen are limiting reactants.

So, for every $2$ $2$ moles of $C_{6} H_{6}$ $C_6H_6$ you will produce $12$ $12$ moles of $C O_{2}$ $CO_2$ and $6$ $6$ moles of $H_{2} O$ $H_2O$ .
GIven that you have $0.5$ $0.5$ moles to start with, you will end up with $3$ $3$ moles of $C O_{2}$ $CO_2$ ( 1:6 ratio ) and $1.5$ $1.5$ moles of $H_{2} O$ $H_2O$ ( 1:3 ratio).

Now, using the ideal gas law $P V = n R T$ $PV = nRT$ and knowing that you have a total of $3 + 1.5 = 4.5$ $3 + 1.5 = 4.5$ moles of gas produced, you get

$V = \frac{n R T}{P} = \frac{4.5 \cdot 0.082 \cdot (105 + 273)}{2.0} = 69.7 L$ $V = (nRT)/P = (4.5 * 0.082 * (105+273))/2.0 = 69.7 L$

Science

Math

Humanities

... and beyond

Question #00893

1 Answer

Related questions

Impact of this question