Question

Question #9e481

Answer 1

The answer is `4.0g`.

We know that molarity is the concentration of a solution expressed by the number of moles of solute per liter of solution. This means that

`C = n_(solute)/(V_(solution)) -> n_(HCl) = C * V_(solution)`

So, `n_(HCl) = 1.5 (mol es)/(L) * 75 * 10^(-3) L = 0.11mol es`

Knowing that `HCl`'s molar mass is equal to `36.5 g/(mol)`, we can determine its mass by

`m_(HCl) = n_(HCl) * 36.5 g/(mol) = 0.11 mol es * 36.5 g/(mol e) = 4.0 g`