Question #7c902

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Answer 1 · 2014-12-13T09:54:52

This is a fairly straightforward pH problem, all you need to know is that

$[H_{3}^{+} O] = 10^{- p H}$ $[H_3^+O] = 10^(-pH)$

Plugging in the pH value will produce

$[H_{3}^{+} O] = 10^{- 8.85} = 0.00000000141 = 1.4 \cdot 10^{- 9} M$ $[H_3^+O] = 10^(-8.85) = 0.00000000141 = 1.4 * 10^(-9) M$

SInce the pH is greater than 7, you are dealing with a basic solution

$p O H = 14 - p H = 14 - 8.85 = 5.15$ $pOH = 14 - pH = 14-8.85 = 5.15$

This means the concentration of $O H^{-}$ $OH^-$ is

$[O H^{-}] = 10^{- p O H} = 10^{- 5.51} = 7.1 \cdot 10^{- 6} M$ $[OH^-] = 10^(-pOH) = 10 ^-5.51 = 7.1 * 10^-6 M$