Question #81931

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Question #81931

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Answer 1 · 2015-01-07T16:21:29

Let's take them one at a time...

Ammonium sulphate - ${(N H_{4})}_{2} S O_{4}$ $(NH_4)_2SO_4$ - $S O_{4}^{2 -}$ $SO_4^(2-)$ is the sulphate ion;

Zinc sulphide - $Z n S$ $ZnS$

Aluminium carbonate - $A l_{2} {(C O_{3})}_{3}$ $Al_2(CO_3)_3$ - $C O_{3}^{2 -}$ $CO_3^(2-)$ is the carbonate ion;

Potassium sulphite - $K_{2} S O_{3}$ $K_2SO_3$ - $S O_{3}^{2 -}$ $SO_3^(2-)$ is the sulfite ion;

${(N H_{4})}_{2} C 2 O_{4}$ $(NH_4)_2C2O_4$ - ammonium oxalate - $N H_{4}^{+}$ $NH_4^(+)$ is the ammonium ion and $C_{2} O_{4}^{-}$ $C_2O_4^(-)$ is the oxalate ion;

$A l_{2} {(S O_{4})}_{3}$ $Al_2(SO_4)_3$ - aluminium sulfate - $S O_{4}^{-}$ $SO_4^(-)$ is the sulfate ion;

${(N H_{4})}_{3} P O_{4}$ $(NH_4)_3PO_4$ - ammonium phosphate - again, $N H_{4}^{+}$ $NH_4^(+)$ is the ammonium ion, while $P O_{4}^{3 -}$ $PO_4^(3-)$ is the phosphate ion;

$L i_{3} N$ $Li_3N$ - Lithium nitride;

Now for the last one, $N a {(C H_{3} C O O)}_{2}$ $Na(CH_3COO)_2$ . Could you have mistyped the compound?

$N a (C H_{3} C O O)$ $Na(CH_3COO)$ is sodium acetate, the salt of acetic acid. Since you have $N a^{+}$ $Na^(+)$ and $C H_{3} C O O^{-}$ $CH_3COO^(-)$ , there cannot be a 2 subscript in the formula.

Another possible compound is $N a H {(C H_{3} C O O)}_{2}$ $NaH(CH_3COO)_2$ , sodium diacetate.

There are quite a few online quizzes that can help you practice naming ionic compounds, here's a link to one:

http://www.quia.com/rr/180365.html

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Question #81931

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