Question #db5d9

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Question #db5d9

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Answer 1 · 2015-01-07T18:43:34

Your general chemical equation is

$C u {(O H)}_{2} (s) + 4 N H_{3} (a q) \to [C u {(N H_{3})}_{4}] {(O H)}_{2} (a q)$ $Cu(OH)_2(s) + 4 NH_3(aq) -> [Cu(NH_3)_4] (OH)_2(aq)$

The ionic equation looks like this:

$C u {(O H)}_{2} (s) + 4 N H_{3} (a q) \to {[C u {(N H_{3})}_{4}]}_{4}^{2 +} (a q) + 2 O H^{-} (a q)$ $Cu(OH)_2(s) + 4 NH_3(aq) -> [Cu(NH_3)_4]^(2+)(aq) + 2OH^(-)(aq)$

Copper (II) hydroxied in ammonia solution is also known as Schweizer's reagent, a chemical used to dissolve cellulose.

${[C u {(N H_{3})}_{4}]}_{4}^{2 +}$ $[Cu(NH_3)_4]^(2+)$ is the tetraamminecopper (II) ion, a complex ion which I believe is also called cuprammonium ion.

Here's a video on some home-made Schweizer's reagent:

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