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Question #c0cfe

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Answer 1 · 2015-01-23T04:21:34

$7 \sum n=3 9 + 4 n^{2} + 4 =$ $sum _"n=3" ^7 9+4n^2+4=$

$7 \sum n=3 4 n^{2} + 13$ $sum _"n=3" ^7 4n^2+13$

These are 5 terms to be added. And you are on the right way, but you forgot to add the $5 \cdot 13 = 65$ $5*13=65$

Actually, I think it strange that the $9$ $9$ and $4$ $4$ are separated. I suspect one of them had a $n$ $n$ attached to it in the original problem.
You always calculate the full expression, for every value of $n$ $n$ from $3$ $3$ up to (and including) $7$ $7$ .

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