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Answer 1 · 2015-04-07T16:03:27

Are you asking about a plot of Boyle's Law?

Boyle's Law is

$P V = k$ $PV = k$ or $P = \frac{k}{V}$ $P = k/V$

There are three common ways of plotting Boyle's Law: $P$ $P$ vs. $V$ $V$ , $P$ $P$ vs. $1/ V$ $"1/"V$ , and $P V$ $PV$ vs. $V$ $V$ .

www.one-school.net

$P$ $P$ vs. $V$ $V$

A plot of $P$ $P$ vs. $V$ $V$ is a hyperbola.

Remember that $\frac{P V}{T} = k$ $(PV)/T = k$ or $P = \frac{k T}{V}$ $P = (kT)/V$ .

If we increase the temperature, the new value of $k T$ $kT$ will be higher, and the new graph will be above the original plot.

www.chem.canterbury.ac.nz

$P$ $P$ vs. $1/ V$ $"1/"V$

Since $P = \frac{k T}{V}$ $P = (kT)/V$ , a plot of $P$ $P$ vs. $1/ V$ $"1/"V$ is a straight line with a slope $k T$ $kT$ starting at the origin.

If $T$ $T$ increases, the slope $k T$ $kT$ increases, and the new graph will be above the original plot.

www.chem.canterbury.ac.nz

$P V$ $PV$ vs. $V$ $V$

A plot of $P V$ $PV$ vs. $V$ $V$ is a horizontal straight line, because $P V = k T = a constant$ $PV = kT = "a constant"$ .

If $T$ $T$ increases, $k T$ $kT$ increases, and we get a new horizontal line above the original plot.

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