Question

Question #0e2bc

Answer 1

Your reactants are acetic acid, `CH_3COOH`, and sodium bicarbonate, `NaHCO_3`.

The reaction will actually take place in two steps. The first step will result in the formation of sodium acetate, `CH_3COONa`, and carbonic acid, `H_2CO_3`. This will be a double replacement reaction.

The carbonic acid will then undergo a decomposition reaction to produce carbond dioxide, `CO_2`, and water, `H_2O`.

`CH_3COOH_((aq)) + NaHCO_(3(s)) -> CH_3COONa_((aq)) + underbrace(H_2CO_(3(aq)))_(color(blue)(CO_2 + H_2O))`

All in all, the reaction will look like this

`CH_3COOH_((aq)) + NaHCO_(3(s)) -> CH_3COONa_((aq)) + CO_(2(g)) + H_2O_((l))`

This is actually the classic vinegar - baking soda reaction.