What are the products of the reaction between silver and a solution of gold(I) nitrate? Between solutions of nitric acid and sodium hydrogen carbonate?

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What are the products of the reaction between silver and a solution of gold(I) nitrate? Between solutions of nitric acid and sodium hydrogen carbonate?

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Answer 1 · 2015-05-21T02:27:40

The products for the first reaction are $Au(s) + {AgNO}_{3} (aq)$ $"Au(s)" + "AgNO"_3"(aq)"$ ; for the second reaction they are ${NaNO}_{3} (aq) + H_{2} O(l) + {CO}_{2} (g)$ $"NaNO"_3"(aq)" + "H"_2"O(l)" + "CO"_2"(g)"$ .

Explanation:

Reaction 1

$Ag(s) + {AuNO}_{3} (aq) \to ?$ $"Ag(s)" + "AuNO"_3"(aq)" → "?"$

This reaction looks like a single displacement .

Since $Ag$ $"Ag"$ is above $Au$ $"Au"$ in the activity series, the reaction will be

$Ag(s) + {AuNO}_{3} (aq) \to Au(s) + {AgNO}_{3} (aq)$ $"Ag(s)" + "AuNO"_3"(aq)" → "Au(s)" + "AgNO"_3"(aq)"$

Reaction 2

${HNO}_{3} (aq) + {NaHCO}_{3} (aq) \to ?$ $"HNO"_3"(aq)"+"NaHCO"_3"(aq)" → "?"$

This reaction looks like a double displacement .

More specifically, it is an acid-base neutralization reaction.

It starts as

${HNO}_{3} (aq) + {NaHCO}_{3} (aq) \to H_{2} {CO}_{3} (aq) + {NaNO}_{3} (aq)$ $"HNO"_3"(aq)"+"NaHCO"_3"(aq)" → "H"_2"CO"_3"(aq)" + "NaNO"_3"(aq)"$

But the carbonic acid decomposes immediately to $H_{2} O$ $"H"_2"O"$ and ${CO}_{2}$ $"CO"_2$ .

$H_{2} {CO}_{3} (aq) \to H_{2} O(l) + {CO}_{2} (g)$ $"H"_2"CO"_3"(aq)" → "H"_2"O(l)" + "CO"_2"(g)"$

The overall reaction is

${HNO}_{3} (aq) + {NaHCO}_{3} (aq) \to {NaNO}_{3} (aq) + H_{2} O(l) + {CO}_{2} (g)$ $"HNO"_3"(aq)"+"NaHCO"_3"(aq)" → "NaNO"_3"(aq)" + "H"_2"O(l)" + "CO"_2"(g)"$

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What are the products of the reaction between silver and a solution of gold(I) nitrate? Between solutions of nitric acid and sodium hydrogen carbonate?

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