Question #80ef0

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Question #80ef0

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Answer 1 · 2015-07-01T12:55:20

The answer is D: di nitrogen tetr oxide

Explanation:

Since nitrogen has many oxides, we need to specify them by using number-prefixes for both nitrogen and oxygen. Usually (but not allways) the mono- (=one)-prefix is omitted.

The nitrogen oxides are:
(the piece between brackets is sometimes omitted)
$N_{2} O$ $N_2O$ dinitrogen monoxide
$N O$ $NO$ nitrogen (mon)oxide
$N_{2} O_{3}$ $N_2O_3$ (di)nitrogen trioxide
$N O_{2}$ $NO_2$ nitrogen dioxide
$N_{2} O_{4}$ $N_2O_4$ (di)nitrogen tetroxide
$N_{2} O_{5}$ $N_2O_5$ (di)nitrogen pentoxide

$N_{2} O_{4}$ $N_2O_4$ does not usually occur as a pure substance, as it is in a dynamic equilibrium with $N O_{2}$ $NO_2$ :

$N_{2} O_{4} \leftrightarrow 2 N O_{2}$ $N_2O_4harr2NO_2$

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Question #80ef0

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