Question #9efd0

1 Answer
Aug 24, 2017

Let each charged sphere have a charge q, have a mass m and make an angle θ with the vertical.

In the initial position of equilibrium electrical force of repulsion F and weight of each sphere is connected through expression

Fmg=tanθ

Using Coulomb's Law and other values we write this as

keq2d2mg=d2(l2(d2)2)12
q=⎜ ⎜ ⎜ ⎜ ⎜mg2ked3(l2(d2)2)12⎟ ⎟ ⎟ ⎟ ⎟12

As the charge starts leaking let x be instantaneous distance between the spheres. The above expression reduces to
q=mg2kex32(l2(x2)2)14

Differentiating both sides with respect to time t we get
dqdt=mg2keddt⎢ ⎢ ⎢x32(l2(x2)2)14⎥ ⎥ ⎥

dqdt=mg2ke⎢ ⎢ ⎢32x12(l2(x2)2)14+(x32)(14)(x2)(l2(x2)2)54⎥ ⎥ ⎥dxdt

dqdt is rate of leakage of charge and velocity dxdt=v. Above expression becomes
1vdqdt=mg2ke⎢ ⎢ ⎢3x122(l2(x2)2)14+x528(l2(x2)2)54⎥ ⎥ ⎥

is the required expression.