Question

Question #2748c

Answer 1

The five aromatic isomers are anisole, benzyl alcohol, and o-, m-, and p-cresol.

Explanation:

Your compound has an "unsaturation value" of 4.

That means it must have four rings and/or double bonds.

I immediately think of a benzene ring, which has one ring and three double bonds.

There are, of course, many other non-aromatic possibilities, but there are too many to include here.

A. Monosubstituted benzene ring

The phenyl ring is `"C"_6"H"_5`, so the rest of the molecule is `"CH"_3"O"`.

The only possibilities are `"–OCH"_3` and `"–CH"_2"OH"`.

One possibility is anisole

The other possibility is benzyl alcohol

B. Disubstituted benzene ring

A disubstituted benzene is `"C"_6"H"_4`.

The other substituents must be `"CH"_4"O"`.

The only possibility is `"–CH"_3` and `"–OH"`.

The compounds are o-, m-, and p-cresol.