Question #9d1d8

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Question #9d1d8

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Answer 1 · 2015-10-04T15:55:15

One option is manganese dioxide.

Explanation:

To be able to produce chlorine gas, ${Cl}_{2}$ $"Cl"_2$ , from hydrochloric acid, $HCl$ $"HCl"$ , you need to use an oxidizing agent capable of oxidizing chlorine from a $- 1$ $color(blue)(-1)$ oxidation state, which it has in hydrochloric acid, to a $0$ $color(blue)(0)$ oxidation state, which it has in chlorine gas.

$H - 1 Cl \to 0 {Cl}_{2}$ $"H" stackrel(color(blue)(-1))("Cl") -> stackrel(color(blue)(0))("Cl"_2)$

One oxidizing agent that can help you get chlorine gas from hydrochloric acid is manganese dioxide, ${MnO}_{2}$ $"MnO"_2$ .

${MnO}_{2(s]} + 4 {HCl}_{(aq]} \to {MnCl}_{2(aq]} + {Cl}_{2(g]} ↑ ⏐ + 2 H_{2} O_{(l]}$ $"MnO"_text(2(s]) + 4"HCl"_text((aq]) -> "MnCl"_text(2(aq]) + "Cl"_text(2(g]) uarr + 2"H"_2"O"_text((l])$

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Question #9d1d8

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