Question #b0d8e
1 Answer
Explanation:
Your goal here is to wirte two equations with two unknowns, the price per item,
Let's say that at the initial price of
#P * x = 45000" " " "color(purple)((1))#
Now the price per item is reduced by
SInce now
#P^(') * (x + 25) = 45000#
This is equivalednt to
#overbrace(90/100 * P)^(color(blue)(=P^('))) * (x+25) = 45000" " " " color(purple)((2))#
Use equation
#P = 45000/x#
and use this value in equation
#90/100 * color(red)(cancel(color(black)(45000)))/x * (x + 25) = color(red)(cancel(color(black)(45000)))#
Solve this equation for
#90/100 * 1/color(red)(cancel(color(black)(x))) * color(red)(cancel(color(black)(x))) + 90/100 * 1/x * 25 = 1#
This is equivalent to
#90x + 2250 = 100x#
#10x = 2250 implies x = 2250/10 = 225#
The initial number of items is thus equal to
#color(purple)((1)) implies P = 45000/225 = color(green)(200)#
So, initially you had
#90/100 * 200 = 180#
which means that you can now buy
#180 * (225 + 25) = 45000#