Question

Question #38499

Answer 1

`0.0835"mol/l"`

Explanation:

`H_2SO_(4(aq))+2NaOH_((aq))rarrNa_2SO_(4(aq))+2H_2O_((l))`

`nNaOH=0.0599xx0.34=0.02`

`:.nH_2SO_4=0.02/2=0.01`

`c=n/v`

`:.[H_2SO_4]=0.01/0.01198=0.835"mol/l"`