Question #f536b
1 Answer
Here's what I got.
Explanation:
The idea here is that you need to use mass of the nucleus and the combined mass of the nucleons it contains to determine the mass defect.
Once you know the mass defect per nucleus, you can use Einstein's equation to determine the binding energy per nucleus, then finally use Avogadro's number to find the binding energy per mole of nuclei.
Now, a nuclues' mass defect tells you the difference between the actual mass of the nucleus and the combined mass of the nucleons it contains.
A nucleon is a proton or a neutron. In your case, you know that the iron-56 nucleus has a mass of
This means that the mass defect for a single iron-56 nucleus will be
color(blue)(M_"defect" = m_"nucleons" - m_"nucleus")Mdefect=mnucleons−mnucleus
M_"defect" = "56.44914 u" - "55.92068 u" = "0.52846 u"Mdefect=56.44914 u−55.92068 u=0.52846 u
Here's where Einstein's equation comes into play. The idea here is that the mass defect of a nucleus can be attributed to the binding energy of the nucleus, which tells you how much energy is required to split the nucleus into its constituent nucleons.
You can therefore, using Einstein's equation, convert the mass defect into binding energy
color(blue)(E = M_"defect" * c^2)" "E=Mdefect⋅c2 , where
The trick now is to realize that you must convert the mass defect from unified atomic mass units, or
By definition, one unified atomic mass unit is approximately equal to
"1 u" = 1.660539 * 10^(-27)"kg"1 u=1.660539⋅10−27kg
This means that the mass defect per nucleus for iron-56 will be equal to
0.52846color(red)(cancel(color(black)("u"))) * (1.660539 * 10^(-27)"kg")/(1color(red)(cancel(color(black)("u")))) = 8.7773 * 10^(-28)"kg"
This means that the binding energy per nucleus for iron-56 will be
E = 8.7753 * 10^(-28) * (299792458)^2 color(white)(x) overbrace("kg m"^2 "s"^(-2))^(color(red)("Joules"))
E = 7.8868 * 10^(-11)"J"
Now, nuclear binding energy is usually given per mole of nuclei. This means that you're going to have to use Avogadro's number to get
7.8868 * 10^(-11)"J"/color(red)(cancel(color(black)("nucleus"))) * (6.022 * 10^(23)color(red)(cancel(color(black)("nuclei"))))/"1 mole" = 4.749 * 10^(13)"J/mol"
Expressed in kilojoules per mole, the answer will be
4.749 * 10^(13)color(red)(cancel(color(black)("J")))/"mol" * "1 kJ"/(1000color(red)(cancel(color(black)("J")))) = color(green)(4.749 * 10^(10)"kJ/mol")
