Question #9322b

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Question #9322b

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Answer 1 · 2016-05-18T23:20:19

${NiCl}_{2} (aq) + NaOH(aq)$ $"NiCl"_2("aq)" + "NaOH(aq)"$ $\to$ $rarr$ ${Ni(OH)}_{2} (s) + NaOH(aq)$ $"Ni(OH)"_2"(s)" + "NaOH(aq")$

Explanation:

This is a double replacement (double displacement) reaction in which the cations and anions of the two reactants switch places. It can be represented by the following example:

AX + BY $\to$ $rarr$ AY + BX

Where A and B are cations and X and Y are anions.

We can now predict the products of this reaction.

${NiCl}_{2} (aq) + NaOH(aq)$ $"NiCl"_2("aq)" + "NaOH(aq)"$ $\to$ $rarr$ ${Ni(OH)}_{2} (s) + NaOH(aq)$ $"Ni(OH)"_2"(s)" + "NaOH(aq")$

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Question #9322b

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