Question #860e0

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Question #860e0

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Answer 1 · 2016-01-26T07:11:26

The correct balanced equation is ${2HNO}_{3} + {Ca(OH)}_{2}$ $"2HNO"_3 + "Ca(OH)"_2"$ $\to$ $rarr$ ${Ca(NO}_{3})_{2} {+ 2H}_{2} O$ $"Ca(NO"_3)_2" + 2H"_2"O"$

Explanation:

You are correct. The balanced equation is ${2HNO}_{3} + {Ca(OH)}_{2}$ $"2HNO"_3 + "Ca(OH)"_2"$ $\to$ $rarr$ ${Ca(NO}_{3})_{2} {+ 2H}_{2} O$ $"Ca(NO"_3)_2" + 2H"_2"O"$ .

Both sides of the equation have 4 H atoms, 2 N atoms, 8 O atoms, and 1 Ca atom. You can replace the term atoms with moles.

The equation does have four coefficients. The coefficient for ${Ca(OH)}_{2}$ $"Ca(OH)"_2"$ and ${Ca(NO}_{3})_{2}$ $"Ca(NO"_3)_2"$ is 1. It is not written but is understood.

It is not unusual for there to be mistakes in a textbook. New math textbooks are sometimes accompanied by an errata sheet. You should let your instructor know about this error.

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Question #860e0

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