Question #8212b

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Question #8212b

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Answer 1 · 2016-02-10T08:43:36

No. On the contrary it appears heavy.

Explanation:

It is a case of quantum mechanics.

Whenever speed of an object is comparable to the speed of light the laws of classical mechanics are no longer valid with rest mass $m_{\circ}$ $m_@$ in the equations.
For such cases the

$E_{t o t a l} = γ . m_{\circ} c^{2}$ $E_(t otal)=gamma. m_@ c^2$
where Lorentz factor $γ \equiv \frac{1}{\sqrt{1 - \frac{v^{2}}{c^{2}}}}$ $gamma-=1/sqrt(1 - v^2/c^2)$

Lorentz factor $γ = 1$ $gamma=1$ only for small values of velocity when $\frac{v^{2}}{c^{2}}$ $v^2/c^2$ in the denominator is small and can be ignored.

Observe what happens to the value of Lorentz factor when $v = c$ $v=c$ . It is a singularity.

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Question #8212b

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