Question #9f671

1 Answer

Let compute g hence

g(x)=lim_(h->0)((x+h)^2 -x^2)/h= lim_(h->0) [x^2+2xh+h^2-x^2]/h= lim_(h->0) [h(2x+h)]/h=2x

Finally g(x)=2x

We want g(x)=2 hence

g(x)=2=>2x=2=>x=1