Question #5d4cd

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Question #5d4cd

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Answer 1 · 2016-05-07T17:06:11

$g (t) = y = 2$ $g(t)=y=2$

Explanation:

Just to make sure about something. The term $g (t)$ $g(t)$ is just a way of identifying a particular formula structure. Also the fact that the formula structure is going to be applied to the variable $t$ $t$

Given: $g (t) = \frac{3}{2} t - \frac{5}{2}$ $g(t)=3/2t-5/2$

For this question: wherever there is a variable $t$ $t$ substitute the value of 3

Write as: $y = \frac{3}{2} t - \frac{5}{2}$ $y=3/2t-5/2$

$y = \frac{3}{2} t - \frac{5}{2} \to y = \frac{3}{2} (3) - \frac{5}{2}$ $color(brown)(y=3/2t-5/2)color(blue)(" " ->" " y= 3/2(3)-5/2$

$y = \frac{9}{2} - \frac{5}{2} = \frac{9 - 5}{2} = \frac{4}{2} = 2$ $y=9/2-5/2" " =" " (9-5)/2" "=" "4/2" "=" "2$

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$Foot note$ $color(blue)("Foot note")$

If you had $g (s)$ $g(s)$ you would write $\frac{3}{2} s - \frac{5}{2}$ $" " 3/2s-5/2$

So if you had $g (t) - g (s)$ $g(t)-g(s)$ you would write $(\frac{2}{3} t - \frac{5}{2}) - (\frac{2}{3} s - \frac{5}{2})$ $(2/3t-5/2)-(2/3s-5/2)$

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Question #5d4cd

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