Question

Question #037a0

Answer 1

It is `a=3^(1/4)`

Explanation:

Hence `a^b=b^a` and `b=9a` we have that

#a^(9a)=(9a)^a=>9a*loga=a*log9a=> a*(9loga-log9a)=0=>loga^9=log9a=> a^9=9a=>a^8=9=>a=9^(1/8)=3^(2/8)=> a=3^(1/4)#