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Question #ddcf4

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Mar 1, 2016

1.29 L

Explanation:

Boyle's Law states that $P_{1} V_{1}$ $P_1V_1$ = $P_{2} V_{2}$ $P_2V_2$

you are given $P_{1}$ $P_1$ (1.1 atm) and $V_{1}$ $V_1$ (4.0L)

you want $P_{2}$ $P_2$ to be 3.4 atm; plug everything in and you get

$(1.1 a t m) \cdot (4.0 L)$ $(1.1atm) * (4.0L)$ = $(3.4 a t m) \cdot (x L)$ $(3.4atm) * (xL)$

Rearrange to solve for x

$\frac{(1.1 a t m) \cdot (4.0 L)}{3.4 a t m}$ $[(1.1atm) * (4.0L)]/(3.4atm)$ = $1.29 L$ $1.29L$

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