At "STP", how many molecules would there be in a 3.28*L volume of H_2S(g)?

1 Answer
Mar 5, 2016

The molar volume of an ideal gas is 22.4 L at STP.

Explanation:

We idealize the behaviour of hydrogen sulfide, and take the quotient:

"Volume of "H_2S = (3.28*L)/(22.4*L*mol^-1) =??mol.

Now 1 mole of gas contains N_A (6.022xx10^23*mol^-1) particles, so:

"No. of molecules" = 6.022xx10^23*mol^-1xx(3.28*L)/(22.4*L*mol^-1) =

??H_2S" particles?"

How smelly would such a quantity of hydrogen sulfide be? You would probably pass out!