At STP, how many molecules would there be in a 3.28L volume of H2S(g)?

1 Answer
Mar 5, 2016

The molar volume of an ideal gas is 22.4 L at STP.

Explanation:

We idealize the behaviour of hydrogen sulfide, and take the quotient:

Volume of H2S = 3.28L22.4Lmol1 =??mol.

Now 1 mole of gas contains NA (6.022×1023mol1) particles, so:

No. of molecules = 6.022×1023mol1×3.28L22.4Lmol1 =

??H2S particles?

How smelly would such a quantity of hydrogen sulfide be? You would probably pass out!